DATEDIF

Owned by Former user (Deleted)
Last updated: Oct 30, 2007 by Former user (Deleted)Version comment

Returns the number of years, months, or days between two dates.

Syntax

Syntax: DATEDIF( DateParam StartDate ; DateParamEndDate ; Text Format )
Returns: Number
Constraints: None
Semantics: Compute difference between StartDate and EndDate, in the units given by Format.

The Format is a code from the following table, entered as text, that specifies the format you want the result of DATEDIF to have.

format

Returns the number of

y

Years

m

Months. If there is not a complete month between the dates, 0 will be returned.

d

Days

md

Days, ignoring months and years

ym

Months, ignoring years

yd

Days, ignoring years

Example

Syntax

Result

=DateDif("2005-01-01"; "2007-05-31"; "y")

=DateDif(Date(2005; 1; 1); Date(2007;5;31); "y")

StartDate =01/01/05
EndDate = 05/01/07 
=DateDif([StartDate]; [EndDate]; "y")

2

=DateDif("2005-01-01"; "2007-05-31"; "m")

28

=DateDif("2005-01-01"; "2007-05-31"; "d")

880

=DateDif("2005-01-01"; "2007-05-31"; "md")

30

=DateDif("2005-01-01"; "2007-05-31"; "ym")

4

=DateDif("2005-01-01"; "2007-05-31"; "yd")

150